(2x-5)^2=x+4

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Solution for (2x-5)^2=x+4 equation: 



(2x-5)^2=x+4

We move all terms to the left:

(2x-5)^2-(x+4)=0

We get rid of parentheses

(2x-5)^2-x-4=0

We add all the numbers together, and all the variables

-1x+(2x-5)^2-4=0

We move all terms containing x to the left, all other terms to the right

-1x+(2x-5)^2=4

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